t^2-(4/3)t-(1/4)=0

Solution for t^2-(4/3)t-(1/4)=0 equation:

t^2-(4/3)t-(1/4)=0


Domain of the equation: 3)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

t^2-(+4/3)t-(+1/4)=0

We multiply parentheses

t^2-4t^2-(+1/4)=0

We get rid of parentheses

t^2-4t^2-1/4=0

We multiply all the terms by the denominator


t^2*4-4t^2*4-1=0

Wy multiply elements

4t^2-16t^2-1=0

We add all the numbers together, and all the variables

-12t^2-1=0

a = -12; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-12)·(-1)
Δ = -48
Delta is less than zero, so there is no solution for the equation